Kevin and Randy muise have a jar containing 55 coins, all of which are either quarters or nickels. The total value of the coins in the jar is $9.35 how many of each type of coin do they have?

Answer:The number of quarters in the jar  =   33The number of nickels  = 22Step-by-step explanation:Let us assume the total number of quarters in the jar  = mNow,as the total number of coins in the jar  = 55SO, the number of nickels in the jar = 55 - mAlso, 1 quarter = $0.25So, m quarters  = m  x ( $0.52) = $ 0.25 m   ...... (1)1 nickel = $0.05So, (55 - m) nickels  = (55 - m)  x ( $0.05) = $ (2.75 - 0.05 m) ..... (2)Total Value in the jar = $9.35⇒ The value of m quarters  +  (55 - m) nickels  = $9.35or,  $ 0.25 m + $ (2.75 - 0.05 m)  = $9.35    ..........           from (1 and 2)or,  0.25 m + 2.75 - 0.05 m =  9.35⇒ 0.2 m =  6 .6or, m  = 6.6/0.2 =  33or, m = 33Hence the number of quarters in the jar = m=  33The number of nickels  = 55 - m = 55 -33 =22