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Given a directed line segment with endpoints A(3, 2) and B(6, 11), what is the point thatdivides AB...
4 months ago
Q:
Given a directed line segment with endpoints A(3, 2) and B(6, 11), what is the point thatdivides AB two-thirds from A to B?
Accepted Solution
A:
The formula for a directed line is:X = K1(X2) + (K2(X1) / K3Y = K1(Y2) + (K2(Y1) / K3K1 = numerator = 2K2 = denominator - numerator = 3-2 = 1K3 = denominator = 3X = (2(6) + 1(3)) /3X = (12+3) / 3X = 12/3X = 5Y = (2(11) + 1(2)) /3Y = (22 + 2) /3Y = 24/3Y = 8The point is (5,8)